32j^2-52j+6=0

Solution for 32j^2-52j+6=0 equation:

Simplifying
32j2 + -52j + 6 = 0

Reorder the terms:
6 + -52j + 32j2 = 0

Solving
6 + -52j + 32j2 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '2'.
2(3 + -26j + 16j2) = 0

Factor a trinomial.
2((1 + -8j)(3 + -2j)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(1 + -8j)' equal to zero and attempt to solve:

Simplifying
1 + -8j = 0

Solving
1 + -8j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -8j = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -8j = 0 + -1
-8j = 0 + -1

Combine like terms: 0 + -1 = -1
-8j = -1

Divide each side by '-8'.
j = 0.125

Simplifying
j = 0.125
Subproblem 2
Set the factor '(3 + -2j)' equal to zero and attempt to solve:

Simplifying
3 + -2j = 0

Solving
3 + -2j = 0

Move all terms containing j to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2j = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2j = 0 + -3
-2j = 0 + -3

Combine like terms: 0 + -3 = -3
-2j = -3

Divide each side by '-2'.
j = 1.5

Simplifying
j = 1.5
Solution
j = {0.125, 1.5}